The discriminant is zero and the only characteristics are the lines t = const. The initial pulse is zero for |x − x₀| > w, yet at t = 0⁺ the blue curve is already non-zero at every x. Only u(x,0) can be prescribed.
Any τ, however small, gives two real characteristics dx/dt = ±√(D/τ). Outside the cone |x − x₀| < w + vt, u is exactly zero. Now u_t(x,0) is also needed; here it is zero, so the pulse splits into two halves that leave a wake behind them.
The ∂u/∂t term damps the waves as e−t/2τ. At late times the yellow curve approaches the blue one. This is how strongly scattered wave energy, such as coda, ends up obeying a diffusion law.
One knob, τ, takes the same equation from the parabolic row of the classification table to the hyperbolic row. The initial pulse and boundary conditions never change. Each “Show this” button sets the demo to the state described and switches back to it.
At τ = 0 the equation is pure diffusion. The initial pulse is zero outside |x − x₀| < w, yet a moment later u is non-zero along the whole line: the signal is felt everywhere instantly. This is the “spreading flow” row of the table.
Go to τ = 0.1. The type jumps to hyperbolic and a light cone appears with v = √(D/τ) ≈ 3.2, yet at t = 3 the yellow curve is almost on top of the blue one. Ask the class what changed. The answer is the characteristics, not the look of the solution.
At τ = 10, press Play from t = 0. The pulse splits into two halves that travel at v ≈ 0.32 and damp slowly as e−t/2τ, leaving a wake between them. Outside the cone u is exactly zero, while the blue diffusion reference has already leaked everywhere.
At τ = 0.1 the fronts reach the grounded ends near t ≈ 6. On the space–time map the characteristics bounce off the walls. Change the speed to 0.5× to follow them.
Set τ = 1 and drag t well past τ. The waves damp out and the yellow curve settles onto the blue one. This leads into the slide on diffusion via strong scattering: at times long compared with the scattering time, wave energy obeys a diffusion law.
A cable with resistance R, inductance L, capacitance C and leakage G per unit length obeys the telegrapher’s equations. Set G = 0 and eliminate the current:
LC∂²V∂t²+RC∂V∂t=∂²V∂x²
Dividing by RC gives exactly the equation above, with
τ = L/RD = 1/(RC)v = 1/√(LC)
So the slider holds the cable fixed (R and C, hence D) and switches on its inductance.